Knowing that $\displaystyle f(x)=tg^2(3x+1)$, the value of $\displaystyle f''(\frac{-1}{3})$ is ?
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Originally Posted by Apprentice123 Knowing that $\displaystyle f(x)=tg^2(3x+1)$, the value of $\displaystyle f''(\frac{-1}{3})$ is ? Since f is a linear function the second derivative is zero for all x.
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