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Thread: Function

  1. March 18th 2009, 09:12 AM #1
    Apprentice123
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    Function

    Knowing that f(x)=tg^2(3x+1), the value of f''(\frac{-1}{3}) is ?
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  2. March 18th 2009, 09:30 AM #2
    earboth
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    Quote Originally Posted by Apprentice123 View Post
    Knowing that f(x)=tg^2(3x+1), the value of f''(\frac{-1}{3}) is ?
    Since f is a linear function the second derivative is zero for all x.
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