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Thread: Function

  1. Mar 18th 2009, 08:12 AM #1
    Apprentice123
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    Function

    Knowing that $\displaystyle f(x)=tg^2(3x+1)$, the value of $\displaystyle f''(\frac{-1}{3})$ is ?
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  2. Mar 18th 2009, 08:30 AM #2
    earboth
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    Quote Originally Posted by Apprentice123 View Post
    Knowing that $\displaystyle f(x)=tg^2(3x+1)$, the value of $\displaystyle f''(\frac{-1}{3})$ is ?
    Since f is a linear function the second derivative is zero for all x.
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