Absolutely lost on this:
r=8cotx (x should be in degrees).
I tried converting this (as well as others) but I seem to just get nowhere after I turned cot into cosx/sinx.
Thanks.
Edit: The equation above should be converted to rectangular form.
Absolutely lost on this:
r=8cotx (x should be in degrees).
I tried converting this (as well as others) but I seem to just get nowhere after I turned cot into cosx/sinx.
Thanks.
Edit: The equation above should be converted to rectangular form.
I think I would have done this a slightly different way:
$\displaystyle r= 8 cot(\theta)= 8\frac{cos(\theta)}{sin(\theta)}$ so
$\displaystyle r sin(\theta)= 8 cos(\theta)$
Multiplying on both sides of the equation by r,
$\displaystyle r(r sin(\theta))= 8 r cos(\theta)$
and
$\displaystyle \sqrt{x^2+ y^2}y= 8x$
Now squaring both sides will give what Mr. fantastic got.