use 9x^2+4y^2+18x-16y-11=0 to do the following:

write the equation in standrad form

9x^2+4y^2+18x-16y-11=0

9x^2+18x+4y^2-16y=11

9(x^2+2) +4(y^2-4y)=11

9[(x^2+2+1)-1] +4[(y^2-4y+4)-4]=11

9[(x+1)^2-1] +4[(y-2)^2-4]=11

9(x+1)^2-9 +4(y-2)^2-16=11

9(x+1)^2+4(y-2)^2=27

9(x+1)^2+4(y-2)^2=27

27 27 27

(x-1)^2+4(y-2)^2=1

3 27

the 27 is divided by4(y-2)^2

is this right?? I think I did something wrong!