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Math Help - Slope/Standard Form

  1. #1
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    Slope/Standard Form

    I really can't do this to save my life and It's homework for tomorrow - I didn't know I had it. Help is much appreciated!!


    it has to do with slope intercept and standard form

    slope intercept form is :y=mx+b
    standard form is ax+by=c (no decimals or fractions)

    point,slope

    m=2,(-4,2)
    m=0,(2,-3)



    two points

    (0,2)(4,-2)
    (-8,6)(-13,1)
    (-4,5)(4,5)
    (2,1)(-1,0)
    (6,-1)(-1,6)
    (3,4)(5,6)



    Write the line in STANDARD form

    y=2x-9
    y=1/2x+2
    (-8,3)m=2
    (-6,-7)m=-1
    (1,3)m=1/2
    (-2,-4)m=3/4
    (9,-2)(-3,2)
    (4,-7)(5,-1)
    (0,4)(2,3)
    (-2,3)(4,-2)

    Working must be shown.

    MUCH THANKS TO WHOEVER CAN HELP.
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  2. #2
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    It is quite urgent :X.
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  3. #3
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    Quote Originally Posted by Josť View Post
    I really can't do this to save my life and It's homework for tomorrow - I didn't know I had it. Help is much appreciated!!


    it has to do with slope intercept and standard form

    slope intercept form is :y=mx+b
    standard form is ax+by=c (no decimals or fractions)

    point,slope

    m=2,(-4,2)
    m=0,(2,-3)

    use the point-slope form ... y - y_1 = m(x - x_1)

    two points

    (0,2)(4,-2)
    (-8,6)(-13,1)
    (-4,5)(4,5)
    (2,1)(-1,0)
    (6,-1)(-1,6)
    (3,4)(5,6)

    find the slope ... m = \frac{y_2-y_1}{x_2-x_1} , then use the point-slope form.
    .
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  4. #4
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    Thanks alot.

    What about the last bit?
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  5. #5
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    Talking

    Quote Originally Posted by Josť View Post
    I really can't do this to save my life...

    Write the line in STANDARD form
    There is no standard definition for "standard form". You'll have to look in your book and / or your class notes for the definition that you're supposed to use.

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