Hi all, i'm a little stuck on this question: Does the perimeter = 3h + πr? Area of the window = h^2 + ( πr^2 / 2)?
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Originally Posted by PIR Hi all, i'm a little stuck on this question: Does the perimeter = 3h + πr? Area of the window = h^2 + ( πr^2 / 2)? No The length of the bottom is 2r and not h The perimeter is 2r + 2h + πr The area is πr²/2 + rh
Originally Posted by running-gag No The length of the bottom is 2r and not h The perimeter is 2r + 2h + πr The area is πr²/2 + rh how do i go about rearranging the equations to find r and h? given that the perimeter has to equal 12meters.
Originally Posted by PIR Hi all, i'm a little stuck on this question: Does the perimeter = 3h + πr? Area of the window = h^2 + ( πr^2 / 2)? Search the forums for threads about norman window eg. http://www.mathhelpforum.com/math-he...w-problem.html and you will probably find your question answered.
its called a norman window!!! Thank you!
Could someone tell me if i simplified this correctly? A =1/2πr^2+2r((12-2r-πr)/2) I got: A=12r-(2+π/2) r^2
Last edited by PIR; Mar 14th 2009 at 03:30 PM.
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