# Math Help - Functions question

1. ## Functions question

2. $f(x)=xf(x)$

$
(x-1)f(x)=0
$

Put $x=2$,which gives $f(2)=0$

Someone should prove that $f(1)=0$ if the answer is indeed $f(1)$

Will you tell me the source of this question

3. the problem is that
f{x} = x f{x}

so, whatever value u put for X, the inequality will never ever hold.

lets take an example x = 2

f{2} = 2* f{2}
1 = 2 (inequality doesnt hold)

f{3} = 3* f{3}
1= 3 {inequality doesnt hold)

the inequality holds IFF f(x) = 0. but,
f(1) = 1 . f{1}
so , f{1} can / cannot be 0. but we cant say for sure.

(have Pmed u the source of the question)