Thread: Volumes and Velocitys

A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

0.009525 m diameter
0.0047625 m radius

A1 = 0.00007122557
A2 = 31.07357
v1 = 0.361 m/s
v2 = 0.000000827469 m/s


Volume Cylinder = PI r² h
volume = pi (3.145)² 1.40
Volume = 43.5 m^2

velocity = 0.361 m/s

This is some of the workings I have completed but i cannot figure out the answer
anyone help please : )
thanks

Hell qzno

Originally Posted by qzno

A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

0.009525 m diameter
0.0047625 m radius

A1 = 0.00007122557
A2 = 31.07357
v1 = 0.361 m/s
Your working is fine up to here. I'm not sure what the next line is...?
v2 = 0.000000827469 m/s


Volume Cylinder = PI r² h
volume = pi (3.145)² 1.40
Volume = 43.5 m^2
This is also correct (units should be m^3)
velocity = 0.361 m/s

This is some of the workings I have completed but i cannot figure out the answer
anyone help please : )
thanks

Thanks for showing us your working so far. That's most helpful. What you now need is:

Area of cross-section of hose = A1 =0.0000712

Water is flowing at a rate of 0.361 . So the volume flowing per sec = 0.0000712 x 0.361 ; i.e. rate of flow = 0.0000257

Volume to deliver = 43.5

So time taken = seconds

days

= about days

Grandad