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Math Help - Volumes and Velocitys

  1. #1
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    Volumes and Velocitys

    A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

    0.009525 m diameter
    0.0047625 m radius

    A1 = 0.00007122557
    A2 = 31.07357
    v1 = 0.361 m/s
    v2 = 0.000000827469 m/s


    Volume Cylinder = PI r h
    volume = pi (3.145) 1.40
    Volume = 43.5 m^2

    velocity = 0.361 m/s

    This is some of the workings I have completed but i cannot figure out the answer
    anyone help please : )
    thanks
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  2. #2
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    Volume and rate of flow

    Hell qzno
    Quote Originally Posted by qzno View Post
    A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

    0.009525 m diameter
    0.0047625 m radius

    A1 = 0.00007122557
    A2 = 31.07357
    v1 = 0.361 m/s
    Your working is fine up to here. I'm not sure what the next line is...?
    v2 = 0.000000827469 m/s


    Volume Cylinder = PI r h
    volume = pi (3.145) 1.40
    Volume = 43.5 m^2
    This is also correct (units should be m^3)
    velocity = 0.361 m/s

    This is some of the workings I have completed but i cannot figure out the answer
    anyone help please : )
    thanks
    Thanks for showing us your working so far. That's most helpful. What you now need is:

    Area of cross-section of hose = A1 =0.0000712 m^2

    Water is flowing at a rate of 0.361 ms^{-1}. So the volume flowing per sec = 0.0000712 x 0.361 m^3; i.e. rate of flow = 0.0000257 m^3s^{-1}

    Volume to deliver = 43.5 m^3

    So time taken = \frac{43.5}{0.0000257} seconds

    =\frac{43.5}{0.0000257\times 3600 \times 24} days

    = about 19\tfrac{1}{2} days

    Grandad
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