1. ## Volumes and Velocitys

A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

0.009525 m diameter

A1 = 0.00007122557
A2 = 31.07357
v1 = 0.361 m/s
v2 = 0.000000827469 m/s

Volume Cylinder = PI r² h
volume = pi (3.145)² 1.40
Volume = 43.5 m^2

velocity = 0.361 m/s

This is some of the workings I have completed but i cannot figure out the answer
thanks

2. ## Volume and rate of flow

Hell qzno
Originally Posted by qzno
A 3/8 in. (inside) diameter garden hose is used to fill a round swimming pool 6.29 m in diameter. How many days will it take to fill the pool to a depth of 1.40 m if water issues from the hose at a speed of 0.361 m/s?

0.009525 m diameter

A1 = 0.00007122557
A2 = 31.07357
v1 = 0.361 m/s
Your working is fine up to here. I'm not sure what the next line is...?
v2 = 0.000000827469 m/s

Volume Cylinder = PI r² h
volume = pi (3.145)² 1.40
Volume = 43.5 m^2
This is also correct (units should be m^3)
velocity = 0.361 m/s

This is some of the workings I have completed but i cannot figure out the answer
thanks
Thanks for showing us your working so far. That's most helpful. What you now need is:

Area of cross-section of hose = A1 =0.0000712 $m^2$

Water is flowing at a rate of 0.361 $ms^{-1}$. So the volume flowing per sec = 0.0000712 x 0.361 $m^3$; i.e. rate of flow = 0.0000257 $m^3s^{-1}$

Volume to deliver = 43.5 $m^3$

So time taken = $\frac{43.5}{0.0000257}$ seconds

$=\frac{43.5}{0.0000257\times 3600 \times 24}$ days

= about $19\tfrac{1}{2}$ days