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Math Help - Vertex of a Parabola

  1. #1
    ADY
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    Vertex of a Parabola

    Bit of help please chaps:

    Finding the vertex of a Parabola, two methods, graph and formula.

    Formula: h= -5h^2 + 10t

    Now when i've graphed it, it comes out positive in terms of co-ordinates, however when you apply the formula:

    Letting a= -5, b= 10, c= 0

    ( - \frac{b}{2a}  ,  C - \frac{b^2}{4a})

    For X Co-Ord

    ( - \frac{10}{2 x ^-5}  ) = -1

    For Y Co-Ord

    0 - \frac{10^2}{4 x -5}) = -5

    The vertex of the parabola on the graph shows X = 1 and Y = 5 so how or why am i getting the negatives?!

    Thanks
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  2. #2
    MHF Contributor
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    a = -5 , b = 10 , c = 0

    x = \frac{-b}{2a} = \frac{-10}{2(-5)} = \frac{-10}{-10} = 1
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