
Solve for x.
e^(x + 3) = pi ^x
I know that e and pi are both constants.
I'm not quite sure what to do next.
I tired taking the log of both sides and then moving the x exponents in front of the log, but if that is right, i'm not sure what to do from there.
Thanks for any help!

Quote:
Originally Posted by
apm e^(x + 3) = pi ^x
$\displaystyle \ln(e^{x+3}) = \ln(\pi^x)
$
$\displaystyle x+3 = x \cdot \ln{\pi}
$
$\displaystyle 3 = x \cdot \ln{\pi}  x$
$\displaystyle 3 = x(\ln{\pi}  1)$
$\displaystyle \frac{3}{\ln{\pi}  1} = x$
