# Solve for x.

• March 4th 2009, 03:47 PM
apm
Solve for x.
e^(x + 3) = pi ^x
I know that e and pi are both constants.
I'm not quite sure what to do next.
I tired taking the log of both sides and then moving the x exponents in front of the log, but if that is right, i'm not sure what to do from there.

Thanks for any help!
• March 4th 2009, 04:33 PM
skeeter
Quote:

Originally Posted by apm
e^(x + 3) = pi ^x

$\ln(e^{x+3}) = \ln(\pi^x)
$

$x+3 = x \cdot \ln{\pi}
$

$3 = x \cdot \ln{\pi} - x$

$3 = x(\ln{\pi} - 1)$

$\frac{3}{\ln{\pi} - 1} = x$
• March 4th 2009, 04:45 PM
apm
thank you!