1. ## Circle!

A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???

2. Originally Posted by andrew93
A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???
What are you trying to do?

The centre of the circle is at (3,-4), and its radius is 5.

RonL

3. Hello, Andrew!

You forgot to tell us what we're supposed to do.
But I can take a guess . . .

A unit circle center at the origin undergoes a series of transformations.
The equation of the resulting graph is: . $(x-3)^2+ (y+4)^2\:= \:25$

It probably asks for the transformations that had taken place.

The original circle was centered at the origin and had radius $1.$

The new circle is centered at $(3,-4)$ and has radius $5.$

The unit circle was moved 3 units to the right and 4 units down,
. . and dilated (enlarged) by a factor of 5.