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Math Help - Circle!

  1. #1
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    Exclamation Circle!

    A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

    So I have to get y by itslef right?
    so:
    (y+4)^2= 25-(x-3)^2
    (y+4)= squar root(25-(x-3)^2)
    y= square root(25-(x-3)^2) -4

    I don't get what to do from here???
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by andrew93 View Post
    A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

    So I have to get y by itslef right?
    so:
    (y+4)^2= 25-(x-3)^2
    (y+4)= squar root(25-(x-3)^2)
    y= square root(25-(x-3)^2) -4

    I don't get what to do from here???
    What are you trying to do?

    The centre of the circle is at (3,-4), and its radius is 5.

    RonL
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  3. #3
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    Hello, Andrew!

    You forgot to tell us what we're supposed to do.
    But I can take a guess . . .


    A unit circle center at the origin undergoes a series of transformations.
    The equation of the resulting graph is: . (x-3)^2+ (y+4)^2\:= \:25

    It probably asks for the transformations that had taken place.

    The original circle was centered at the origin and had radius 1.

    The new circle is centered at (3,-4) and has radius 5.


    The unit circle was moved 3 units to the right and 4 units down,
    . . and dilated (enlarged) by a factor of 5.

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