# Circle!

• Nov 16th 2006, 12:15 PM
andrew93
Circle!
A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???:confused:
• Nov 16th 2006, 12:21 PM
CaptainBlack
Quote:

Originally Posted by andrew93
A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???:confused:

What are you trying to do?

The centre of the circle is at (3,-4), and its radius is 5.

RonL
• Nov 17th 2006, 05:53 PM
Soroban
Hello, Andrew!

You forgot to tell us what we're supposed to do.
But I can take a guess . . .

Quote:

A unit circle center at the origin undergoes a series of transformations.
The equation of the resulting graph is: .\$\displaystyle (x-3)^2+ (y+4)^2\:= \:25\$