Circle!

A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???:confused:

Quote:

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Originally Posted by andrew93

A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25

So I have to get y by itslef right?
so:
(y+4)^2= 25-(x-3)^2
(y+4)= squar root(25-(x-3)^2)
y= square root(25-(x-3)^2) -4

I don't get what to do from here???:confused:

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What are you trying to do?

The centre of the circle is at (3,-4), and its radius is 5.

RonL

Hello, Andrew!

You forgot to tell us what we're supposed to do.
But I can take a guess . . .

Quote:

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A unit circle center at the origin undergoes a series of transformations.
The equation of the resulting graph is: .

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It probably asks for the transformations that had taken place.

The original circle was centered at the origin and had radius

The new circle is centered at and has radius


The unit circle was moved 3 units to the right and 4 units down,
. . and dilated (enlarged) by a factor of 5.