I have to rearrange the following, making p the subject of the equation:
ln(p) = β0 + β1x
I have got P = e^(β0 + β1x) Is this correct
Yes it is correct but you can use the rules of exponentials to say that $\displaystyle e^{(\beta0 + \beta1x)} = e^\beta0 * e^{(\beta1x)}$
$\displaystyle If we say that \alpha = e^{\beta0}$ then we get
$\displaystyle p = \alpha e^{(\beta1x)}$
This assumes $\displaystyle \beta0$ is a constant, if it is not constant than ignore this whole post