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Math Help - [SOLVED] Natural Logarithm

  1. #1
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    [SOLVED] Natural Logarithm

    I have to rearrange the following, making p the subject of the equation:

    ln(p) = β0 + β1x

    I have got P = e^(β0 + β1x) Is this correct
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Orangeobe View Post
    I have to rearrange the following, making p the subject of the equation:

    ln(p) = β0 + β1x

    I have got P = e^(β0 + β1x) Is this correct
    yes
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  3. #3
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by Jhevon View Post
    yes
    Yes it is correct but you can use the rules of exponentials to say that e^{(\beta0 + \beta1x)} = e^\beta0 * e^{(\beta1x)}

    If we say that \alpha = e^{\beta0} then we get

    p = \alpha e^{(\beta1x)}

    This assumes \beta0 is a constant, if it is not constant than ignore this whole post
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