I have to rearrange the following, making p the subject of the equation:

ln(p) = β0 + β1x

I have got P = e^(β0 + β1x) Is this correct

Printable View

- February 28th 2009, 09:06 AMOrangeobe[SOLVED] Natural Logarithm
I have to rearrange the following, making p the subject of the equation:

ln(p) = β0 + β1x

I have got P = e^(β0 + β1x) Is this correct - February 28th 2009, 09:13 AMJhevon
- February 28th 2009, 09:23 AMe^(i*pi)