# [SOLVED] Natural Logarithm

• Feb 28th 2009, 08:06 AM
Orangeobe
[SOLVED] Natural Logarithm
I have to rearrange the following, making p the subject of the equation:

ln(p) = β0 + β1x

I have got P = e^(β0 + β1x) Is this correct
• Feb 28th 2009, 08:13 AM
Jhevon
Quote:

Originally Posted by Orangeobe
I have to rearrange the following, making p the subject of the equation:

ln(p) = β0 + β1x

I have got P = e^(β0 + β1x) Is this correct

yes
• Feb 28th 2009, 08:23 AM
e^(i*pi)
Quote:

Originally Posted by Jhevon
yes

Yes it is correct but you can use the rules of exponentials to say that $e^{(\beta0 + \beta1x)} = e^\beta0 * e^{(\beta1x)}$

$If we say that \alpha = e^{\beta0}$ then we get

$p = \alpha e^{(\beta1x)}$

This assumes $\beta0$ is a constant, if it is not constant than ignore this whole post