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Math Help - Finding the equation of a straight line...is this right?

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    Smile Finding the equation of a straight line...is this right?

    Find the equation of a straight line having the gradient given and passing through the point listed. Express your answer in the form i) ax + by + c= 0 and ii) y= mx + c.

    (3,-2) gradient= -1

    y --2 = -1(x -3)
    y + 2 = -x + 3 y + 2= -x + 3
    ii) y = -x + 1 i) -x - y + 1 = 0

    Is this right so far? Because in my textbook it says for i) x + y -1 = 0 instead of what I did. It also shows a few other different answers to what I did with some of my other questions.

    Thanks!
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    Quote Originally Posted by Joker37 View Post
    Find the equation of a straight line having the gradient given and passing through the point listed. Express your answer in the form i) ax + by + c= 0 and ii) y= mx + c.

    (3,-2) gradient= -1

    y --2 = -1(x -3)
    y + 2 = -x + 3 y + 2= -x + 3
    ii) y = -x + 1 i) -x - y + 1 = 0

    Is this right so far? Because in my textbook it says for i) x + y -1 = 0 instead of what I did. It also shows a few other different answers to what I did with some of my other questions.

    Thanks!
    Your answer to i) is the same answer, you've just swapped the signs (it is still correct but generally x should always be positive by convention). If you move everything over to the other side you will get what the book says.

    ii) looks good
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