Does anyone understand these two problems:
Problem 1:
(hint: )
Problem 2:
help please?
for 1, I got -2k
& for 2, I got 3
which were wrong
Incorporating the hint, this is equivalent to:
$\displaystyle \log_{1048576}\left[\left(\left[1048576^{\frac{1}{10}}\right]^{-2}\right)^k\right]=\log_{1048576}\left[\left(1048576\right)^{-\frac{2k}{10}}\right]$ $\displaystyle =-\frac{k}{5}\log_{1048576}\left(1048576\right)=\col or{red}\boxed{-\frac{k}{5}}$
Note that $\displaystyle 3^{6\log_3 5-5\log_3 6}=3^{6\log_3 5}3^{-5\log_3 6}=3^{\log_3\left(5^6\right)}3^{\log_3\left(6^{-5}\right)}$Problem 2:
help please?
for 1, I got -2k
& for 2, I got 3
which were wrong
Can you finish the simplification?
Does this make sense?
In the hint, $\displaystyle 1048576=4^{10}\implies 1048576^{\frac{1}{10}}=4$. Thus, in your expression, I substituted $\displaystyle 1048576^{\frac{1}{10}}$ for $\displaystyle 4$.
Does this clarify things?
I applied rules of exponents:& on problem 2,
i am very lost.
where did the 3 come from in between 5 and -5
$\displaystyle a^{b-c}=a^ba^{-c}$