Hello, Engineer Adam,

the point you are looking for belongs to the perpendicular bisector of the two given pointsandthe straight line parallel to the x-axis with y = 3.

1. Calculate the midpoint between the given points: M(5, 1)

2. Calculate the slope of the line connecting the given points:

Therefore the perpendicular direction has the slope -2/3

3. Use point-slope-formula of a straight line:

4. Plug in this value for y and solve for x. You should get x = 2

So the point you are looking for is P(2, 3)

EB

PS.: The 2nd problem is very similar to this one here. I leave for you.