Our topic is about distance formulas:
1.) If the point is equidistant from and find
2.) Find the point on the y - axis which is equidistant from
thank you very much
Hello, Engineer Adam,
the point you are looking for belongs to the perpendicular bisector of the two given points and the straight line parallel to the x-axis with y = 3.
1. Calculate the midpoint between the given points: M(5, 1)
2. Calculate the slope of the line connecting the given points:
Therefore the perpendicular direction has the slope -2/3
3. Use point-slope-formula of a straight line:
4. Plug in this value for y and solve for x. You should get x = 2
So the point you are looking for is P(2, 3)
EB
PS.: The 2nd problem is very similar to this one here. I leave for you.
Hello, ^_^Engineer_Adam^_^!
Our topic is about distance formulas. . Really?
Here's an idea . . . How about using the Distance Formula?
. . . . .1) If the point is equidistant from and find
Distance
Distance
Since , we have: .
Square both sides: .
And we have: .
2) Find the point on the y - axis which is equidistant from and
A point on the y-axis has the form:
Then: .
Hence: .
Therefore: . . . The point is