h(x) = (16x9 - 15)3; f(x) = x3
find g(x)
Hello keadyjrThanks for clarifying it a bit. I'm still not absolutely sure what the question says, but I think it could be this:
Find the function $\displaystyle g$ such that $\displaystyle h = f \circ g$, if $\displaystyle h(x) = (16x^9-15)^3$ and $\displaystyle f(x) = x^3$.
If this is so, then you need to say this:
$\displaystyle h = f \circ g \Rightarrow h(x) = f(g(x))$
$\displaystyle = (g(x))^3$
$\displaystyle = (16x^9-15)^3$
So $\displaystyle g(x) = 16x^9 -15$
Grandad