# precalc

• Feb 21st 2009, 11:31 PM
precalc
h(x) = (16x9 - 15)3; f(x) = x3

find g(x)
• Feb 22nd 2009, 01:03 AM
Quote:

h(x) = (16x9 - 15)3; f(x) = x3

find g(x)

Sorry, this doesn't make sense. Can we see the original question, please?

• Feb 22nd 2009, 09:07 AM
precalc
Find function g such that h = f http://www.webassign.net/images/composite.gif g. h(x) = (16x9 - 15)3; f(x) = x3

G(x) =
• Feb 22nd 2009, 10:17 AM
Combining functions
Quote:

Find function g such that h = f http://www.webassign.net/images/composite.gif g. h(x) = (16x9 - 15)3; f(x) = x3

G(x) =

Thanks for clarifying it a bit. I'm still not absolutely sure what the question says, but I think it could be this:

Find the function \$\displaystyle g\$ such that \$\displaystyle h = f \circ g\$, if \$\displaystyle h(x) = (16x^9-15)^3\$ and \$\displaystyle f(x) = x^3\$.

If this is so, then you need to say this:

\$\displaystyle h = f \circ g \Rightarrow h(x) = f(g(x))\$

\$\displaystyle = (g(x))^3\$

\$\displaystyle = (16x^9-15)^3\$

So \$\displaystyle g(x) = 16x^9 -15\$