# precalc

Printable View

• February 21st 2009, 11:31 PM
keadyjr
precalc
h(x) = (16x9 - 15)3; f(x) = x3

find g(x)
• February 22nd 2009, 01:03 AM
Grandad
More information please
Hello keadyjr
Quote:

Originally Posted by keadyjr
h(x) = (16x9 - 15)3; f(x) = x3

find g(x)

Sorry, this doesn't make sense. Can we see the original question, please?

Grandad
• February 22nd 2009, 09:07 AM
keadyjr
precalc
Find function g such that h = f http://www.webassign.net/images/composite.gif g. h(x) = (16x9 - 15)3; f(x) = x3

G(x) =
• February 22nd 2009, 10:17 AM
Grandad
Combining functions
Hello keadyjr
Quote:

Originally Posted by keadyjr
Find function g such that h = f http://www.webassign.net/images/composite.gif g. h(x) = (16x9 - 15)3; f(x) = x3

G(x) =

Thanks for clarifying it a bit. I'm still not absolutely sure what the question says, but I think it could be this:

Find the function $g$ such that $h = f \circ g$, if $h(x) = (16x^9-15)^3$ and $f(x) = x^3$.

If this is so, then you need to say this:

$h = f \circ g \Rightarrow h(x) = f(g(x))$

$= (g(x))^3$

$= (16x^9-15)^3$

So $g(x) = 16x^9 -15$

Grandad