Thread: Sine to cosine shift

Explain how y = 4sinθ can be written as a cosine function.

Thanks for any help!

I'm not exactly sure how you want it, but...

sinθ = cos((pi/2)-θ) (in radians)

Therefore, you could write y = 4sinθ as y = 4cos((pi/2)-θ)

Originally Posted by XanthanPower

I'm not exactly sure how you want it, but...

sinθ = cos((pi/2)-θ) (in radians)

Therefore, you could write y = 4sinθ as y = 4cos((pi/2)-θ)

Thanks for the help