Explain how y = 4sinθ can be written as a cosine function. Thanks for any help!
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I'm not exactly sure how you want it, but... sinθ = cos((pi/2)-θ) (in radians) Therefore, you could write y = 4sinθ as y = 4cos((pi/2)-θ)
Originally Posted by XanthanPower I'm not exactly sure how you want it, but... sinθ = cos((pi/2)-θ) (in radians) Therefore, you could write y = 4sinθ as y = 4cos((pi/2)-θ) Thanks for the help
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