# Thread: [SOLVED] inverse of a function

1. ## [SOLVED] inverse of a function

I think that I did this right but I am unsure
2x-3/x+1
=x-3/x+2

2. Originally Posted by roachbeats
I think that I did this right but I am unsure
2x-3/x+1
=x-3/x+2
You are close, you just have sign errors:

Starting with

$y = \frac{2x-3}{x+1}$

Switch your x & y terms:

$x = \frac{2y-3}{y+1}$

x(y+1) = 2y-3

xy - 2y = -x-3

y(x-2) = -x-3

$y = \frac{-x-3}{x-2}$