I think that I did this right but I am unsure 2x-3/x+1 =x-3/x+2
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Originally Posted by roachbeats I think that I did this right but I am unsure 2x-3/x+1 =x-3/x+2 You are close, you just have sign errors: Starting with $\displaystyle y = \frac{2x-3}{x+1}$ Switch your x & y terms: $\displaystyle x = \frac{2y-3}{y+1}$ x(y+1) = 2y-3 xy - 2y = -x-3 y(x-2) = -x-3 $\displaystyle y = \frac{-x-3}{x-2}$
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