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Thread: [SOLVED] inverse of a function

  1. February 18th 2009, 07:27 PM #1
    roachbeats
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    [SOLVED] inverse of a function

    I think that I did this right but I am unsure
    2x-3/x+1
    =x-3/x+2
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  2. February 18th 2009, 07:47 PM #2
    mollymcf2009
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    Quote Originally Posted by roachbeats View Post
    I think that I did this right but I am unsure
    2x-3/x+1
    =x-3/x+2
    You are close, you just have sign errors:

    Starting with

    y = \frac{2x-3}{x+1}

    Switch your x & y terms:

    x = \frac{2y-3}{y+1}

    x(y+1) = 2y-3

    xy - 2y = -x-3

    y(x-2) = -x-3

    y = \frac{-x-3}{x-2}
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