Hi Lucy,

First find the slope of the perpendicular by putting the equation in slope-intercept form ( ).

The slope is

Now the slope of a line perpendicular to this line will have a slope that is the negative reciprocal. So, the slope for our new line will be .

Let substitute the point , and the slope, , into the point slope form.

graphs a horizontal line that crosses the y axis at , thus your y-intercept is . The slope of a horizontal line (line parallel to the x-axis) is always 0.