Hello,

Im having some trouble with the error approximations in relation to Taylor series.

For example [Math]f(x) = x^{1/3}[/tex] about $\displaystyle x=8$; approximate $\displaystyle 9^{1/3}$

[Math]f(x)= (x+8)^{1/3}[/tex]

$\displaystyle f'(x) = 1/3(x+8)^{-2/3}$

$\displaystyle f''(x) = -2/9(x+8)^{-5/3}$

$\displaystyle f(1) = 2 + 1/12 - 1/288$

However i just can't get my head around how to do the error approximation.

/Jones