Results 1 to 3 of 3

Thread: Taylor series and error approximations

  1. #1
    Member Jones's Avatar
    Joined
    Apr 2006
    From
    Norway
    Posts
    170

    Taylor series and error approximations

    Hello,

    Im having some trouble with the error approximations in relation to Taylor series.

    For example [tex]f(x) = x^{1/3}[/tex] about x=8; approximate 9^{1/3}

    [tex]f(x)= (x+8)^{1/3}[/tex]
    f'(x) = 1/3(x+8)^{-2/3}
    f''(x) = -2/9(x+8)^{-5/3}

    f(1) = 2 + 1/12 - 1/288

    However i just can't get my head around how to do the error approximation.

    /Jones
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    14,787
    Thanks
    3007
    note that the series is alternating ... error < |first omitted term|
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member Jones's Avatar
    Joined
    Apr 2006
    From
    Norway
    Posts
    170
    Hmm, how do you mean?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Taylor Series Error Estimation
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Nov 13th 2011, 04:44 PM
  2. Taylor series approximations
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Jan 22nd 2011, 06:23 PM
  3. Taylor Series of the Error Function
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Feb 15th 2010, 04:29 PM
  4. taylor series and error
    Posted in the Calculus Forum
    Replies: 0
    Last Post: Mar 16th 2009, 04:06 PM
  5. error factor of Taylor Series
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Apr 12th 2008, 10:02 AM

Search Tags


/mathhelpforum @mathhelpforum