For this function how do you determine what time interval the ball will be more than 40 feet in the air?
I am assuming t is time. As said max height is 50 at t=5. Due to symmetry of the curve it should be [5-a, 5+a].
20t-2t^2=40 gives you the solution.
I think it is: [5-sqrt(5), 5+sqrt(5)].
P.S. I knew that plot of an object is a parabolla, f(x)=ax^2+bx+c, where x is the horizontal range. BUT I am not sure if it is still a parobolla when it is written with respect to time: f(t). Would that trajectory happen on the Jupiter?