Hey, I don't get how as x approaches 1 x-2/(x-1)^2 = negative infinite

Help is very appreciated, Thanks

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- Feb 15th 2009, 07:44 PMMudd_101Infinite limits
Hey, I don't get how as x approaches 1 x-2/(x-1)^2 = negative infinite

Help is very appreciated, Thanks - Feb 15th 2009, 07:50 PMwytiaz
When you get arbitrarily close to 1:

- the bottom becomes closer and closer to zero. Since it's being squared, it will be positive whether you approach from the left or right.

- the top will get closer and closer to negative one from either side.

So what you have, as you approach 1, is a negative value that is growing (because the denominator is shrinking).