Thread: [SOLVED] help w/ asytopes, roots, etc

1. [SOLVED] help w/ asytopes, roots, etc

The root(s) of , in increasing order, is/are: , , .

has hole(s) when x is: , , .

has vertical asymptotes when x is: , , .

list the vertical asymptotes in increasing order.
has a horizontal asymptote at

Hint: -4 is a zero of both numerator and denominator, use synthetic division to find more of each.

2. Originally Posted by lsnyder

The root(s) of , in increasing order, is/are: , , .

Factor the top. This will give you your roots.

has hole(s) when x is: , , .

Factor the denominator. Any factors from the denominator that can be canceled from the denominator and numerator are holes in your graph

has vertical asymptotes when x is: , , .

x = a is a vertical asymptote of the graph of f(x) if: as f(x) approaches infinity, x approaches a from the right $f(x) \rightarrow \infty$, $(x \rightarrow a^+)$or as f(x) approaches negative infinity, x approaches a from the left $f(x)\rightarrow -\infty$ as $(x \rightarrow a^-)$

From the denominator factors, after canceling any factors, the remaining factors from your denominator will be vertical asymptotes.

list the vertical asymptotes in increasing order.
has a horizontal asymptote at

Hint: -4 is a zero of both numerator and denominator, use synthetic division to find more of each.
Have you learned to do synthetic division?

3. I've already done the work. I only got half the problem right. I meant for someone to explain to see what I did was wrong. Like comparing and checking what went wrong.

so far I got:

F(x) has holes : -4
&
the horizonal asymptotes: y=1

4. now i got the roots

5. Originally Posted by lsnyder
I've already done the work. I only got half the problem right. I meant for someone to explain to see what I did was wrong. Like comparing and checking what went wrong.

so far I got:

F(x) has holes : -4
&
the horizonal asymptotes: y=1
You didn't have any of your work on there and there were no answers on your first post.

Your answer for the hole and horizontal asymptote are correct. Look at the directions I gave you to find the other answers, try them again and if you would like me to check the answers for you I will be happy to do that. Did you use synthetic division to find your other roots?

6. How can you expect people to tell you what you did wrong if you won't show us what you did?

7. Originally Posted by lsnyder
I've already done the work. I only got half the problem right. I meant for someone to explain to see what I did was wrong. Like comparing and checking what went wrong.
If you want to check your work, post it here so that we can point out any specific problems. Don't ask us to waste our time writing full solutions with which you can compare your answers.

8. I am not trying to be mean but I have 58 problems to figure out which all are just as long. I just don't have the time to write it all out when I have so much.

It wasn't I am lazy or wanting answers, I truly want to learn the material. It's just hard when I have so much & my professor is from India and has a accent which is hard to understand. I am trying my best.

So if everyone can stop giving me so much grief, I would appreciate it. I am trying to learn.

9. Originally Posted by lsnyder
I am not trying to be mean but I have 58 problems to figure out which all are just as long. I just don't have the time to write it all out when I have so much.

It wasn't I am lazy or wanting answers, I truly want to learn the material. It's just hard when I have so much & my professor is from India and has a accent which is hard to understand. I am trying my best.

So if everyone can stop giving me so much grief, I would appreciate it. I am trying to learn.
We aren't giving you grief! You asked for us to check your answers and there weren't any answers there! We want to help you, but you need to be specific on what you want help on! Re-read your original post. It looks like you don't know what you need to do to solve it. Next time say something like, "I got my horizontal asymptote, but I dont know how to get the other things" Ok?