I have been working on this problem all day...can anyone help me? Problem: ln(2x+3/X^2-3x+2)^2 I got 2ln(2)+2ln(x)+2ln(3)-4ln(x)-2ln(-3x)-2ln(2).... Can anyone help?
Follow Math Help Forum on Facebook and Google+
Originally Posted by tuckergrl I have been working on this problem all day...can anyone help me? Problem: ln(2x+3/X^2-3x+2)^2 I got 2ln(2)+2ln(x)+2ln(3)-4ln(x)-2ln(-3x)-2ln(2).... Can anyone help? $\displaystyle \ln\left(\frac{2x+3}{x^2-3x+2}\right)^2$ $\displaystyle 2\ln\left(\frac{2x+3}{x^2-3x+2}\right)$ $\displaystyle 2\ln\left(\frac{2x+3}{(x-2)(x-1)}\right)$ $\displaystyle 2[\ln(2x+3) - \ln(x-2) - \ln(x-1)]$
View Tag Cloud