Problem:
By completing the square, the expression (x^2)+2x+164 equals ((x+A)^2)+B where A=______ and B=_______.
I found A, which is 1
but I can't figure out B.
help please
hello,
you need to equal the equation to zero , then pass 164 to the other side of the equation .
so you will have x^2+ 2x = -164.
Then, you need multiply 2x by 1/2. The result, which is 1, must be written on both sides of the equation.
x^2+2x+1= -164+1
At this point, you have already completed the square, and you only need to reduce both sides of the equation.
(x+1)^2 = -163
(x+1)^2 + 163
Therefore, a = 1 and b = 163