# Math Help - Slope of Tangent???

1. ## Slope of Tangent???

Hey, I really have no idea how to do this so help is greatly appreciated

Use the equation of the slope of a secant line to find the slope of the secant line passing through (2,4) on y = x^2, where h = 1.

I believe the equation of the secant slope is {f(a+h) - f(a)}/h

but again, not that sure..

thanks

2. Originally Posted by Mudd_101
Use the equation of the slope of a secant line to find the slope of the secant line passing through (2,4) on y = x^2, where h = 1.

I believe the equation of the secant slope is {f(a+h) - f(a)}/h
This is true, but it may work better to think about what it means, rather than memorizing an equation.

If h=1, you want a point where the x is 1 more than the point you're starting with. (If h=2, you want a point where the x is 2 more, etc.)

The point you're starting with has $x=2$, so you want a point where $x=2+1=3$.

Then go back to your equation and plug in x=3:
$y=(3)^2=9$

Then just find an equation of the line passing through (2,4) and (3,9).

3. Got it Right!!! , Thanks