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Math Help - Slope of Tangent???

  1. #1
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    Slope of Tangent???

    Hey, I really have no idea how to do this so help is greatly appreciated

    Use the equation of the slope of a secant line to find the slope of the secant line passing through (2,4) on y = x^2, where h = 1.

    I believe the equation of the secant slope is {f(a+h) - f(a)}/h

    but again, not that sure..


    thanks
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  2. #2
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    Quote Originally Posted by Mudd_101 View Post
    Use the equation of the slope of a secant line to find the slope of the secant line passing through (2,4) on y = x^2, where h = 1.

    I believe the equation of the secant slope is {f(a+h) - f(a)}/h
    This is true, but it may work better to think about what it means, rather than memorizing an equation.

    If h=1, you want a point where the x is 1 more than the point you're starting with. (If h=2, you want a point where the x is 2 more, etc.)

    The point you're starting with has x=2, so you want a point where x=2+1=3.

    Then go back to your equation and plug in x=3:
    y=(3)^2=9
    So your point is (3,9).

    Then just find an equation of the line passing through (2,4) and (3,9).
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  3. #3
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    Got it Right!!! , Thanks
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