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**Slipery** I have a Secants question that I have to hand in tomorrow morning, and it just seems a bit odd to me.. Anyone mind helping me out? I asked this before but didn't receive an answer:

67 An automobile's distance is given by d=30t (t in seconds, d in metres)

a) Graph the function (it is a straight line)

b) Draw the secants from the point (2,60) to each of the points on the graph ending at t=3,2.5,2.1,1.01

c) Determine the equations of each of the secants above

d) Explain your results from c

Will not all of my secants run straight through my line? How can I even draw them if I am drawing 4 lines on top of each other?

The equations of my secants will be different because they start at different points on the line.. Does anyone know why they want me to draw 4 secants through the same line?

Thanks