Originally Posted by
kn336a Hi My question is:
Find the point on the line 4x-2y+3=0 that is equidistant from (3,3) and (7,-3)
I'm still a little confused about what to do.
Some ideas: I set 4x-2y+3=0 to y=2x + 3/2
and that gives me the y-intercept
Now, I was thinking that I need to find x with a distance formula.
For example, find the distance formula for (3,3), then a second distance formula for (7,-3) and equal them to each other. Plugging in the y-intercept, then solving for x. I tried that, but I had an odd answer.
If anybody could help me out that would be great! thanks