Let f(x) = 3 + x^2 + tan((pi x)/2) where -1 is less than x is less than 1. (a) Find f inverse(3) (b) Find f(f inverse(5)) Thank you
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Originally Posted by question111 Let f(x) = 3 + x^2 + tan((pi x)/2) where -1 is less than x is less than 1. (a) Find f inverse(3) note that $\displaystyle f(0) = 3$ (b) Find f(f inverse(5)) $\displaystyle f[f^{-1}(x)] = x$
I understand, thank you.
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