First find the column vector AB = (5, -5, -5)
vector AP = 3/5 vector AB
vector AP = 3/5(5, -5, -5)
vector AP = (3, -3, -3)
So move 3, -3 and -3 from A (-1, 6, 4) to find the co-ordinates of P.
Use vectors to find the position vector of point 'P' if 'P' divides AB in the ratio 3:2 given A(-1,6,4) and B(4,1,-1).
This is what I'm thinking so far..
Point P is 3/5 the way along from A to B. When you divide something in the ratio 3:2, one part will be 3/5 of the total and the other will be 2/5 of the total.
coordinates of P are (x, y, z), the position vector of point P will be the vector (x - (-1), y - 6, z - 4). This vector has the same direction as AP and the same magnitude.
Am I on the right track here fellas?
Hello everyone -
You'll find that the answer is simply
where, of course and are the position vectors of A and B. Which simply says that P's position is two-fifths of A's plus three-fifths of B's.
Can you see why this is? As you were saying, you move to P by moving to A and then three-fifths of the way from A to B. So:
And you can generalise this, and say that if P divides AB in the ratio , then
(Notice how the and have 'swapped' over.)
I hope you find this useful.
Grandad