Can someone walk me through this? Solve for x using using natural logarithms. Answer should be in decimal approximations rounded to the nearest thousandth. 3 ∙ 7^x = 2 ∙ 5^x

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Hey Originally Posted by Humbled_by_math Can someone walk me through this? Solve for x using using natural logarithms. Answer should be in decimal approximations rounded to the nearest thousandth. 3 ∙ 7^x = 2 ∙ 5^x using ln ln(3) + x * ln(7) = ln(2) +ln(5)x solve for x and you get x = -1.205... Rapha

Thank you.