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Math Help - Pre-calc problem: Minimizing distance

  1. #1
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    Pre-calc problem: Minimizing distance

    At 2:00 PM bike A is 4km north of point C and traveling south at 16km/h. At the same time, bike B is 2km east of C and traveling east at 12km/h.

    a. Show that t hours after 2:00 PM the distance between the bikes is:
    square root of 400t^2 - 80t + 20

    b. At what time is the distance between the bikes the least?


    Help would really be appreciated!
    Thanks!!!
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  2. #2
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    Quote Originally Posted by Juice08 View Post
    At 2:00 PM bike A is 4km north of point C and traveling south at 16km/h. At the same time, bike B is 2km east of C and traveling east at 12km/h.

    a. Show that t hours after 2:00 PM the distance between the bikes is:
    square root of 400t^2 - 80t + 20

    b. At what time is the distance between the bikes the least?


    Help would really be appreciated!
    Thanks!!!
    bike A's distance from C ...

    d_A = 4 - 16t

    bike B's distance from point C ...

    d_B = 2 + 12t

    distance between the two bikes at any time t ...

    D = \sqrt{d_A^2 + d_B^2}

    how were you taught to minimize ... with or w/o calculus?
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by skeeter View Post
    how were you taught to minimize ... with or w/o calculus?
    the title indicates that this is for a precalculus class, so i guess w/o calculus is the way to go
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  4. #4
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    Thanks!

    With a calculator....i can take it from here...thank you so much guys!!!
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  5. #5
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    Quote Originally Posted by Juice08 View Post
    With a calculator....i can take it from here...thank you so much guys!!!
    ?? How do you use a calculator to find a minimum value?
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  6. #6
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    Quote Originally Posted by HallsofIvy View Post
    ?? How do you use a calculator to find a minimum value?
    graph the function and find the min ... it's really amazing what graphing calculators can do these days.
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