1. ## Linear Inequalities

Determine whether point P is a solution of the linear inequality.

1. y ≤ -2x + 1; P(2,2)

2. x < 2; P(1,0)

3. y ≥ 3x-2; P(0,0)

4. y > x - 1; P(0,1)

5. y ≥ -2/5x + 4; P(0,0)

6. y > 5/3x - 4; P(0,1)

Thanks for helping me understand these problems!

2. I will give you some work as soon as i am done trying to figure this out!

3. ## Here is my work!

y ≤ -2x + 1; P(2,2)

(cant transfer the graph that i drew onto the cpu)
I just don't know how you are supposed to know if it is a linear inequality!!

4. Originally Posted by amberkraidich
Determine whether point P is a solution of the linear inequality.

1. y ≤ -2x + 1; P(2,2)

2. x < 2; P(1,0)

3. y ≥ 3x-2; P(0,0)

4. y > x - 1; P(0,1)

5. y ≥ -2/5x + 4; P(0,0)

6. y > 5/3x - 4; P(0,1)

Thanks for helping me understand these problems!
Hi amber,

You don't have to graph these inequalities to determine if the ordered pair is in the solution set. Just "plug and chug" the ordered pair into the inequality and see if it makes it true or not.

$y \leq -2x+1$

P(x, y) = P(2, 2)

$2 \leq -2(2)+1$

$2 \leq -4+1$

$2 \leq -3$

This statement is not true, so P(2, 2) is not part of the solution set.

Do this for the others now.