# Math Help - Limit Problem

1. ## Limit Problem

Please explain how to solve it.
Find lim (2x^2 + 5) x is approaching -2

my answer is 13. 2 x (-2)^2 + 5 = 13 My understanding is: when x ia approaching -2, y is approaching 13,
The correct answer is does not exist. Why?

Thank you

2. Are you sure you have the correct problem?. The limit definitely exists and you are right...it is 13 from both directions.

$\lim_{x\to -2}(2x^{2}+5)=13$

3. Thank you very much.