Please explain how to solve it. Find lim (2x^2 + 5) x is approaching -2 my answer is 13. 2 x (-2)^2 + 5 = 13 My understanding is: when x ia approaching -2, y is approaching 13, The correct answer is does not exist. Why? Thank you
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Are you sure you have the correct problem?. The limit definitely exists and you are right...it is 13 from both directions. $\displaystyle \lim_{x\to -2}(2x^{2}+5)=13$
Thank you very much.
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