# Limit Problem

• February 4th 2009, 06:46 AM
oceanmd
Limit Problem
Please explain how to solve it.
Find lim (2x^2 + 5) x is approaching -2

my answer is 13. 2 x (-2)^2 + 5 = 13 My understanding is: when x ia approaching -2, y is approaching 13,
The correct answer is does not exist. Why?

Thank you
• February 4th 2009, 07:35 AM
galactus
Are you sure you have the correct problem?. The limit definitely exists and you are right...it is 13 from both directions.

$\lim_{x\to -2}(2x^{2}+5)=13$
• February 4th 2009, 08:37 AM
oceanmd
Thank you very much.