Please explain how to solve it.

Find lim (2x^2 + 5) x is approaching -2

my answer is 13. 2 x (-2)^2 + 5 = 13 My understanding is: when x ia approaching -2, y is approaching 13,

The correct answer isdoes not exist. Why?

Thank you

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- Feb 4th 2009, 06:46 AMoceanmdLimit Problem
Please explain how to solve it.

Find lim (2x^2 + 5) x is approaching -2

my answer is 13. 2 x (-2)^2 + 5 = 13 My understanding is: when x ia approaching -2, y is approaching 13,

The correct answer is**does not exist**. Why?

Thank you - Feb 4th 2009, 07:35 AMgalactus
Are you sure you have the correct problem?. The limit definitely exists and you are right...it is 13 from both directions.

$\displaystyle \lim_{x\to -2}(2x^{2}+5)=13$ - Feb 4th 2009, 08:37 AMoceanmd
Thank you very much.