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Math Help - [SOLVED] Find the Domain: f(x) = 2e^(2 - x) + 1

  1. #1
    Junior Member moonman's Avatar
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    [SOLVED] Find the Domain: f(x) = 2e^(2 - x) + 1

    Find the domain of this function:

    f(x) = 2e^(2 - x) + 1

    I'm having a very difficult time with this problem.
    I do know that e is always positive and therefore the domain must be all real numbers right?
    I just can't work it out algebraically.

    f(x) = 2e^(2 - x) + 1
    Last edited by moonman; February 3rd 2009 at 10:14 PM.
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  2. #2
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    Quote Originally Posted by moonman View Post
    Find the domain of this function:

    f(x) = 2e^(2 - x) + 1

    I'm having a very difficult time with this problem.
    I do know that e is always positive and therefore the domain must be all real numbers right?
    I just can't work it out algebraically.

    f(x) = 2e^(2 - x) + 1
    Since f(x)=e^x has the domain \mathbb{R} the domain of your function is \mathbb{R} too.

    But if you ask for the range of the function then r = (1,\infty)
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  3. #3
    Junior Member moonman's Avatar
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    Quote Originally Posted by earboth View Post
    Since f(x)=e^x has the domain \mathbb{R} the domain of your function is \mathbb{R} too.

    But if you ask for the range of the function then r = (1,\infty)
    What do you mean by R?
    So there will be no alegebra involved in this problem?
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  4. #4
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    Quote Originally Posted by moonman View Post
    What do you mean by R?
    So there will be no alegebra involved in this problem?
    1. \mathbb{R} is the set of all real numbers.

    2. An addition of real numbers yields a real number too. Therefore (2-x) will be a real number and therefore all possible values of (2-x)~\wedge~x\in \mathbb{R} belong to the domain of f.
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