Hi,

I need help solving a log equation for x algebraically:

This is the equation:2log2(x-6) - log2x = 3

Help is much appreciated!This is what I have so far:

2log2(x-6) - log2x = 3(both logs are base 2)

log2(x-6)^2 - log2x = 3

Im not sure what the next step I should take to solve is?

Any thoughts?

Thanks!

Jim.