I need help solving a log equation for x algebraically:
This is the equation: 2log2(x-6) - log2x = 3
Help is much appreciated!This is what I have so far:
2log2(x-6) - log2x = 3 (both logs are base 2)
log2(x-6)^2 - log2x = 3
Im not sure what the next step I should take to solve is?