Determine the slope of a line perpendicular to each of the following:
a. y = 3x - 5
b. 13x - 7y - 11 = 0
Please help me with this problem, thanks
Okay, I'll take part a, then you can try b..
a. y = 3x - 5
If a line L is perpendicular to M, then the slope of M * slope of L = -1
So first we need to find the slope of our line, y = 3x - 5.
The general equation of a line is expressed as y = mx + c where m is the slope, and c is some constant. So in our case c = -5, and m = 3.
So the slope of the line a = 3.
Now for a slope to be perpendicular,
slope of a*slope of new line = -1.
3 * slope of new line = -1
slope of new line = -1/3.
So the slope of the perpendicular line is -1/3.
The method for b is the same...
Thanks a lot!
I know how to solve part b now.
Simply find the slope of 13x-7y-11=0
simplify the function first, then we got y=13/7x-11/7, the slope is 13/7
Since slope of b * slope of new line = -1
Therefore, the slope of a line perpendicular to 13x-7y-11=0 is -7/13.