Results 1 to 5 of 5

Math Help - [SOLVED] Limits

  1. #1
    Member >_<SHY_GUY>_<'s Avatar
    Joined
    Jan 2008
    From
    CA
    Posts
    181

    Question [SOLVED] Limits

    this part of finding the limit [in this form] ALWAYS confuses me, i really can get it [maybe the (h) throws me off]

    the limit of [f(x+h)-f(x)] / h
    1. f(x) = 3x-1

    How does 3x-1 substitute in when there is an "h", it is confusing
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Hello,
    Quote Originally Posted by >_<SHY_GUY>_< View Post
    this part of finding the limit [in this form] ALWAYS confuses me, i really can get it [maybe the (h) throws me off]

    the limit of [f(x+h)-f(x)] / h
    1. f(x) = 3x-1

    How does 3x-1 substitute in when there is an "h", it is confusing
    f({\color{red}x})=3{\color{red}x}-1

    f({\color{red}x+h})=3({\color{red}x+h})-1


    So \frac{f(x+h)-f(x)}{h}=\frac{[3(x+h)-1]-[3x-1]}{h}=\frac{3x+3h-1-3x+1}{h}=\frac{3h}{h}

    Simplify
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor red_dog's Avatar
    Joined
    Jun 2007
    From
    Medgidia, Romania
    Posts
    1,251
    Thanks
    3
    \lim_{h\to 0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to 0}\frac{[3(x+h)-1]-(3x-1)}{h}=\lim_{h\to 0}\frac{3x+3h-1-3x+1}{h}=

    =\lim_{h\to 0}\frac{3h}{h}=3
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member >_<SHY_GUY>_<'s Avatar
    Joined
    Jan 2008
    From
    CA
    Posts
    181
    Quote Originally Posted by Moo View Post
    Hello,

    f({\color{red}x})=3{\color{red}x}-1

    f({\color{red}x+h})=3({\color{red}x+h})-1


    So \frac{f(x+h)-f(x)}{h}=\frac{[3(x+h)-1]-[3x-1]}{h}=\frac{3x+3h-1-3x+1}{h}=\frac{3h}{h}

    Simplify
    hmm...right...but it says [and i forgot to mention that x approaches zero [the limit] the answer 3?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member >_<SHY_GUY>_<'s Avatar
    Joined
    Jan 2008
    From
    CA
    Posts
    181
    nevermind....errrrr im so dumb...thank you, i get it now haha
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 7th 2009, 07:53 AM
  2. [SOLVED] limits
    Posted in the Differential Geometry Forum
    Replies: 3
    Last Post: April 23rd 2009, 09:19 AM
  3. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 4
    Last Post: March 26th 2009, 07:25 PM
  4. [SOLVED] Limits
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 3rd 2009, 08:13 PM
  5. [SOLVED] [SOLVED] Limits. LIMITS!
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 25th 2008, 10:41 PM

Search Tags


/mathhelpforum @mathhelpforum