$\displaystyle f(x) = x + 1 $ $\displaystyle g(x) = x + \sqrt{x-1}$ I need help to solve $\displaystyle (gof)(x)$.
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same way to solve it as ur last post (gof)x= (x+1)+ squar root of (x+1-1)= (x+1)+suqar root of (x)
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