$\displaystyle f(x) = x + \frac{1}{x^2}$

$\displaystyle g(x) = \frac{1}{x}$

I need to do $\displaystyle (fog)(x)$ and $\displaystyle (gof)(x)$.

I'm not getting the correct answers...I really have problems simplifying. Thanks in advanced!

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- Jan 31st 2009, 06:05 PMtiarCombining Functions
$\displaystyle f(x) = x + \frac{1}{x^2}$

$\displaystyle g(x) = \frac{1}{x}$

I need to do $\displaystyle (fog)(x)$ and $\displaystyle (gof)(x)$.

I'm not getting the correct answers...I really have problems simplifying. Thanks in advanced! - Jan 31st 2009, 06:23 PMshannon1111
For (fog)(x), take g and SHOVE IT INTO f, like this

(fog)(x) = ((1/x) +1/((1/x)^2)

For (gof)(x), take F and SHOVE IT INTO g, like this

(gof)(x) = 1/(x+1/x^2) - Jan 31st 2009, 06:47 PMtiar
Thank you, I was doing the opposite. Yet I'm having problems solving (gof). I'm not getting the correct answer, and I'm sure it's to do with my lack of algebraic knowledge.