Find the slope-intercept equation of the line that passes through (-8, 9) and is perpendicular tox- 8y= 2.

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- Jan 31st 2009, 11:36 AMkeadyjrFinding the equation of a line
Find the slope-intercept equation of the line that passes through (-8, 9) and is perpendicular to

*x*- 8*y*= 2. - Jan 31st 2009, 11:44 AMred_dog

Here m' is the slope of the perpendicular.

The equation is where - Jan 31st 2009, 11:48 AMmasters
Hi keadyjr,

First of all find the slope of your line given by the equation x - 8y = 2. Let's put it in slope-intercept form:

So the slope is

The slope of a line perpendicular to this line would be the negative reciprocal of , or .

Using the point (-8, 9) and a slope of -8, we can now find the y-intercept.

Substituting back into the slope intercept form, we arrive at: