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If a circle with its centre at the origin has a chord with slope ,
the equation of the right bisector of the chord is:
Is this statement true or false? . . . . falseChord has slopeCode:A | o * * * * * * | * * * | * * | * * * | * * * - - * - - - - * - - - - o - - * | * B | * | * * | * * | * * * * |
The perpendicular bisector of the chord does pass through the origin,
. . but its slope is
Its equation is: .