Hello, Joanne!

Did you make a sketch?

If a circle with its centre at the origin has a chord with slope ,

the equation of the right bisector of the chord is:

Is this statement true or false? . . . . falseChord has slopeCode:A | o * * * * * * | * * * | * * | * * * | * * * - - * - - - - * - - - - o - - * | * B | * | * * | * * | * * * * |

The perpendicular bisector of the chord does pass through the origin,

. . but its slope is

Its equation is: .