find h(f(g(x)) f(x) = x^2 + 4 g(x) = [square root of 2x - 3 ] / x + 3 h(x) = 2x - 1 / x + 3 I have 4x + 1 / 2x + 3 Is this correct?

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Hello, Originally Posted by moonman find h(f(g(x)) f(x) = x^2 + 4 g(x) = [square root of 2x - 3 ] / x + 3 h(x) = 2x - 1 / x + 3 I have 4x + 1 / 2x + 3 Is this correct? I think that you forgot to square (x+3) when computing f(g(x)) I get something like $\displaystyle \frac{9x^2+58x+75}{8x^2+50x+49}$

Originally Posted by Moo Hello, I think that you forgot to square (x+3) when computing f(g(x)) I get something like $\displaystyle \frac{9x^2+58x+75}{8x^2+50x+49}$ I did indeed forget to square. Thank you my friend.

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