# Math Help - [SOLVED] h(f(g(x))

1. ## [SOLVED] h(f(g(x))

find h(f(g(x))

f(x) = x^2 + 4
g(x) = [square root of 2x - 3 ] / x + 3
h(x) = 2x - 1 / x + 3

I have 4x + 1 / 2x + 3
Is this correct?

2. Hello,
Originally Posted by moonman
find h(f(g(x))

f(x) = x^2 + 4
g(x) = [square root of 2x - 3 ] / x + 3
h(x) = 2x - 1 / x + 3

I have 4x + 1 / 2x + 3
Is this correct?
I think that you forgot to square (x+3) when computing f(g(x))

I get something like $\frac{9x^2+58x+75}{8x^2+50x+49}$

3. Originally Posted by Moo
Hello,

I think that you forgot to square (x+3) when computing f(g(x))

I get something like $\frac{9x^2+58x+75}{8x^2+50x+49}$
I did indeed forget to square. Thank you my friend.