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Math Help - [SOLVED] h(f(g(x))

  1. #1
    Junior Member moonman's Avatar
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    [SOLVED] h(f(g(x))

    find h(f(g(x))

    f(x) = x^2 + 4
    g(x) = [square root of 2x - 3 ] / x + 3
    h(x) = 2x - 1 / x + 3

    I have 4x + 1 / 2x + 3
    Is this correct?
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  2. #2
    Moo
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    Hello,
    Quote Originally Posted by moonman View Post
    find h(f(g(x))

    f(x) = x^2 + 4
    g(x) = [square root of 2x - 3 ] / x + 3
    h(x) = 2x - 1 / x + 3

    I have 4x + 1 / 2x + 3
    Is this correct?
    I think that you forgot to square (x+3) when computing f(g(x))

    I get something like \frac{9x^2+58x+75}{8x^2+50x+49}
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  3. #3
    Junior Member moonman's Avatar
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    Quote Originally Posted by Moo View Post
    Hello,

    I think that you forgot to square (x+3) when computing f(g(x))

    I get something like \frac{9x^2+58x+75}{8x^2+50x+49}
    I did indeed forget to square. Thank you my friend.
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