[SOLVED] h(f(g(x))

**moonman** · January 29th 2009, 09:53 PM

find h(f(g(x))

f(x) = x^2 + 4
g(x) = [square root of 2x - 3 ] / x + 3
h(x) = 2x - 1 / x + 3

I have 4x + 1 / 2x + 3
Is this correct?

**Moo** · January 29th 2009, 10:06 PM

Hello,

Originally Posted by moonman

find h(f(g(x))

f(x) = x^2 + 4
g(x) = [square root of 2x - 3 ] / x + 3
h(x) = 2x - 1 / x + 3

I have 4x + 1 / 2x + 3
Is this correct?

I think that you forgot to square (x+3) when computing f(g(x))

I get something like $\frac{9x^2+58x+75}{8x^2+50x+49}$

**moonman** · January 30th 2009, 08:53 AM

Originally Posted by Moo

Hello,

I think that you forgot to square (x+3) when computing f(g(x))

I get something like $\frac{9x^2+58x+75}{8x^2+50x+49}$

I did indeed forget to square. Thank you my friend.

Thread: [SOLVED] h(f(g(x))