Problem: f(x)=x^3, find f^-1 (-8) help please
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Originally Posted by lsnyder Problem: f(x)=x^3, find f^-1 (-8) help please $\displaystyle y = x^3 \implies x=\sqrt[3]{y}$ $\displaystyle f^{-1}(x) = \sqrt[3]{x}$ Can you find $\displaystyle f^{-1}(8)$ now?
Originally Posted by lsnyder Problem: f(x)=x^3, find f^-1 (-8) help please Solve -8 = x^3: x = -2. Therefore f(-2) = -8. Therefore by definition $\displaystyle f^{-1}(-8) = -2$.
Originally Posted by Chop Suey $\displaystyle y = x^3 \implies x=\sqrt[3]{y}$ $\displaystyle f^{-1}(x) = \sqrt[3]{x}$ Can you find $\displaystyle f^{-1}(8)$ now? yes thank u very much
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