So I have a problem that I have all parts figured out except for the final part of the question.

The function is f(x)=(x^2 - 1) / (2x^2 - 2x).

The function is discontinuous at 0 and 1.

x=0 is a vertical asymptote.

The horizontal asymptote is y=1/2

Now the final part of the question is:Since there is only one vertical asymptote, indicate on the graph what occurs at the other point of discontinuity. Be specific by giving numerical values.

I am really unsure what happens here. Does the point not exist? I'm confused Any help would be appreciated