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Math Help - Discontinuity and Vertical Asymptotes Help

  1. #1
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    Discontinuity and Vertical Asymptotes Help

    So I have a problem that I have all parts figured out except for the final part of the question.

    The function is f(x)=(x^2 - 1) / (2x^2 - 2x).

    The function is discontinuous at 0 and 1.

    x=0 is a vertical asymptote.

    The horizontal asymptote is y=1/2

    Now the final part of the question is: Since there is only one vertical asymptote, indicate on the graph what occurs at the other point of discontinuity. Be specific by giving numerical values.

    I am really unsure what happens here. Does the point not exist? I'm confused Any help would be appreciated
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  2. #2
    Senior Member mollymcf2009's Avatar
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    It is a hole on the graph of the function at x=1 It is just one point on the graph where the function does not exist. You would just draw an open dot on that point.

    If you plug f(1) into your function it will confirm it for you!! Good luck!!
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