[SOLVED] Find the average rate of change

**moonman** · January 29th 2009, 01:45 PM

Find the average rate of change for: f(x) = x^2 - 3x + 5
a) [2 , 4]
b) [a , a + h]

**skeeter** · January 29th 2009, 02:25 PM

$\frac{f(4) - f(2)}{4 - 2} $

$\frac{f(a+h) - f(a)}{(a+h) - a}$

work them out.

**moonman** · January 29th 2009, 09:41 PM

For a) I have: -8

For b) I have: h^2 + 2ah - 6a + 3h - 10 / 2

Is this correct?

**skeeter** · January 30th 2009, 04:51 AM

$f(4) = 4^2 - 3(4) + 5 = 9$

$ f(2) = 2^2 - 3(2) + 5 = 3 $

$\frac{f(4) - f(2)}{4 - 2} = \frac{9 - 3}{4 - 2} = \, ?$

$ f(a+h) = (a+h)^2 - 3(a+h) + 5 = a^2 + 2ah + h^2 - 3a - 3h + 5 $

$ f(a) = a^2 - 3(a) + 5 = a^2 - 3a + 5 $

$\frac{f(a+h) - f(a)}{(a+h) - a} = \frac{2ah + h^2 - 3h}{h} = \, ?$

work on your algebra.

**moonman** · January 30th 2009, 10:00 AM

Originally Posted by skeeter

$f(4) = 4^2 - 3(4) + 5 = 9$

$ f(2) = 2^2 - 3(2) + 5 = 3 $

$\frac{f(4) - f(2)}{4 - 2} = \frac{9 - 3}{4 - 2} = \, ?$

$ f(a+h) = (a+h)^2 - 3(a+h) + 5 = a^2 + 2ah + h^2 - 3a - 3h + 5 $

$ f(a) = a^2 - 3(a) + 5 = a^2 - 3a + 5 $

$\frac{f(a+h) - f(a)}{(a+h) - a} = \frac{2ah + h^2 - 3h}{h} = \, ?$

work on your algebra.

hehehe yes I need to.

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