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Math Help - hi i really need help on this stuff

  1. #1
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    hi i really need help on this stuff

    i dont really suck at math...

    i blame my teacher... he doesnt know how to teach...
    he doesnt explain the problems very well..

    im switching my teacher next week.. bleh....


    please i really need help =3


    2) standard form 9i - 3i^2

    6)rational zero test
    2x^3-2x^2+2x-10

    8) (1/2)^x=228

    9) if logw = logx+1/2logp then w = ?

    10) if f(x) = x^2-x+1 then f(2a) = ?

    12) x^2+x-3=0 root = ? < --- not sure
    Last edited by KyrieKaye; January 27th 2009 at 09:52 PM. Reason: done some of the questions
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  2. #2
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    Quote Originally Posted by KyrieKaye View Post
    ...

    6)rational zero test
    2x^3-2x^2+2x-10

    8) (1/2)^x=228

    9) if logw = logx+1/2logp then w = ?

    10) if f(x) = x^2-x+1 then f(2a) = ?

    12) x^2+x-3=0 root = ? < --- not sure
    to #6:

    Plug in the values \pm1,\ \pm2,\ \pm5,\ \pm10 and check if the term becomes zero.

    to #8:

    \left(\frac12\right)^x=228~\implies~\left(2\right)  ^{-x}=228~\implies~ -x=\log_2(228)~\implies~ x=-\log_2(228)

    But if the original problem reads:

    \left(\frac12\right)^x=128~\implies~\left(2\right)  ^{-x}=2^7~\implies~ -x=7~\implies~ x=-7

    to #9:
    Use the log rules:
    a\log(x)=\log(x^a)

    \log(a) + \log(b) = \log(a\cdot b)

    The final result should be: w = \sqrt{px^2}

    to #10:
    You are asked to plug in 2a instead of x:

    f(2a) = (2a)^2-(2a)+1

    to #12:
    Solve x^2+x-3=0 . Use the formula to solve a quadratic equation.

    The equation

    ax^2+bx+c=0 has the solution x=\dfrac{-b \pm\sqrt{b^2-4ac}}{2a}
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  3. #3
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    thank you soo much...
    its much clearer to me now
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